Problem 7 A particle of mass \(m\) moves i... [FREE SOLUTION] (2024)

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Chapter 6: Problem 7

A particle of mass \(m\) moves in the potential \(V(x, y, z)=V_{1}(x,y)+V_{2}(z)\) where $$ V_{1}(x, y)=\frac{1}{2} m \omega^{2}\left(x^{2}+y^{2}\right), \quadV_{2}(z)=\left\\{\begin{array}{ll} 0, & 0 \leq z \leq a \\ +\infty, & \text { elsewhere } \end{array}\right. $$ (a) Calculate the energy levels and the wave function of this particle. (b) Let us now turn off \(V_{2}(z)\) (i.e., \(m\) is subject only to \(V_{1}(x, y)\)). Calculate the degeneracy \(g_{n}\) of the \(n\) th energy level (note that\(n=n_{x}+n_{y}\) ).

Short Answer

Expert verified

The energy levels of the particle are given by \(E_{total} = (n_x + 1/2)\hbar\omega + (n_y + 1/2)\hbar\omega + \frac{n^2\pi^2\hbar^2}{2m a^2}\), with wave functions \(\Psi_{n_x, n_y, n}(x, y, z)\). The degeneracy \(g_n\) for the \(n\)th level of 2D harmonic oscillator when \(V_2(z)\) is turned off is \(n + 1\).

Step by step solution

01

Identify the Quantum Mechanics Problem Type

Recognize that the given potential energy function for the particle, separated into two components, suggests a problem compatible with quantum mechanics. The part \(V_1(x, y)\) corresponds to a two-dimensional harmonic oscillator, whereas \(V_2(z)\) suggests a particle in a box for the \(z\)-axis within the range of \(0\) to \(a\). Due to the infinite potential elsewhere, the particle is confined to this box.

02

Solve the 2D Harmonic Oscillator

For the two-dimensional harmonic oscillator part with potential \(V_1(x, y)\), treat the \(x\) and \(y\) components separately to find the quantum states. Energy levels for each dimension are given by \(E_{n_x, n_y} = (n_x + 1/2)\hbar\omega + (n_y + 1/2)\hbar\omega\), where \(n_x\) and \(n_y\) are the quantum numbers for the respective axes. The wave function is the product of the individual wave functions for each axis, \(\psi_{n_x}(x)\psi_{n_y}(y)\).

03

Solve the Particle in a 1D Infinite Potential Box

For the part \(V_2(z)\), treat the motion on the \(z\)-axis as a particle in a one-dimensional infinite potential box with the potential being zero inside the box and infinite outside it. The energy levels are given by \(E_n = \frac{n^2\pi^2\hbar^2}{2m a^2}\) and the wave functions by \(\psi_n(z) = \sqrt{\frac{2}{a}} \sin(\frac{n\pi z}{a})\), where \(n\) is the quantum number, and \(a\) is the width of the potential box.

04

Combine the Results

Combine the results from the two previous steps to find the total energy and wave function of the particle in the complete potential \(V(x, y, z)\). The total energy is the sum of the energies from \(V_1(x, y)\) and \(V_2(z)\). The wave function is the product of the wave functions from the 2D harmonic oscillator and the particle in a box: \(\Psi_{n_x, n_y, n}(x, y, z) = \psi_{n_x}(x)\psi_{n_y}(y)\psi_n(z)\) and energies are \(E_{total} = E_{n_x, n_y} + E_n\).

05

Degeneracy without \(V_2(z)\)

With \(V_2(z)\) turned off, we are left with only the 2D harmonic oscillator. The degeneracy of the \(n\)th energy level is equal to the number of ways in which two non-negative integers (\(n_x, n_y\)) can add up to \(n\), where \(n = n_x + n_y\). This is a combinatorial problem and the degeneracy is \(g_n = n + 1\), for \(n\) starting from 0.

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Two-Dimensional Harmonic Oscillator

The concept of a two-dimensional harmonic oscillator extends from the familiar simple harmonic motion we encounter in classical physics. In quantum mechanics, it refers to the behavior of a particle confined in a quadratic potential well that depends on two spatial dimensions.

In mathematical terms, the potential energy for such a system is defined as:
\[ V_1(x, y) = \frac{1}{2} m \omega^2(x^2 + y^2) \].
Here, \( m \) is the particle's mass, and \( \omega \) is the angular frequency of the oscillator. The harmonic oscillator is a fundamental model because it provides a solvable quantum system that can approximate the behavior near the equilibrium points of more complicated systems.

In quantum mechanics, the energy of a two-dimensional harmonic oscillator is quantized, implying that the particle can only occupy certain discrete energy states. The energy levels are given by:
\[ E_{n_x, n_y} = \left(n_x + \frac{1}{2}\right)\hbar\omega + \left(n_y + \frac{1}{2}\right)\hbar\omega \],
where \( \hbar \) is the reduced Planck's constant, and \( n_x \) and \( n_y \) are the quantum numbers associated with the motion in the \( x \) and \( y \) axes, respectively. The corresponding wave functions are products of the one-dimensional oscillator wave functions for each axis.

Particle in a 1D Infinite Potential Box

The particle in a one-dimensional infinite potential box is another cornerstone model of quantum mechanics. It provides a straightforward scenario in which the wave function of a particle is constricted within a region, with the potential outside being infinitely high.

The potential in this model can be described as:
\[ V_2(z) = \begin{cases} 0, & 0 \leq z \leq a \ +\infty, & \text{elsewhere} \end{cases} \].

This condition leads to the particle being confined to a 'box' of width \( a \). The quantization of energy levels arises due to the wave nature of quantum particles, which requires the wave function to have nodes at the boundaries of the box. The distinct energy levels are:
\[ E_n = \frac{n^2\pi^2\hbar^2}{2m a^2} \],
where \( n \) is the principle quantum number and can take positive integer values starting from 1. Each energy state corresponds to a unique wave function given by:
\[ \psi_n(z) = \sqrt{\frac{2}{a}} \sin\left(\frac{n\pi z}{a}\right) \].
These results emerge from applying boundary conditions to the Schrödinger equation, which governs the behavior of quantum systems.

Quantum Energy Levels

Quantum energy levels are an essential feature of quantum systems. Unlike classical systems where a particle's energy can vary continuously, quantum mechanics stipulates that particles can only have specific, discrete energy values. This is one reason quantum systems are said to be quantized.

The existence of quantum energy levels can be visualized by comparing it to a ladder where a particle can only stand on the rungs and not in between. These levels are determined by solving the Schrödinger equation for the system and are dependent on the boundary conditions and the nature of the potential experienced by the particle.

The specific allowed energy levels for the combined system of a two-dimensional harmonic oscillator and a particle in a 1D infinite potential box are expressed as:
\[ E_{total} = E_{n_x, n_y} + E_n \],
where \( E_{total} \) represents the total energy, \( E_{n_x, n_y} \) comes from the 2D harmonic oscillator, and \( E_n \) from the particle in a 1D box. Each of these energy levels correspond to permissible states the particle can occupy, with transitions between levels typically involving the absorption or emission of energy, such as a photon.

Quantum Wave Functions

Wave functions in quantum mechanics are fundamental descriptions of the state of a quantum system. They are complex functions that contain all the information about a system's properties, such as position and momentum. The probability density associated with the position of a particle is given by the square of the modulus of the wave function.

For the 2D harmonic oscillator, the wave function is separable into the product of two one-dimensional oscillator wave functions. Similarly, for the particle in a one-dimensional box, the wave function is a sine function that conforms to the boundary conditions of the problem.

Upon combining the state functions for each independent scenario, the complete wave function for a particle subject to both potentials, when applicable, is:
\[ \Psi_{n_x, n_y, n}(x, y, z) = \psi_{n_x}(x)\psi_{n_y}(y)\psi_n(z) \].

This product of wave functions ensures that the combined wave function is still a solution to the Schrödinger equation for the overall system. The wave function's squared modulus represents the probability distribution to find the particle in space.

Quantum Degeneracy

Quantum degeneracy occurs when two or more quantum states share the same energy level. In classical physics, each state corresponds to a unique energy value, but quantum mechanics allows for the possibility of these states 'piling up' to form degenerate states.

For the two-dimensional harmonic oscillator, the degeneracy is determined by the number of ways the quantum numbers \( n_x \) and \( n_y \) can sum up to a particular value of \( n = n_x + n_y \), where \( n \) is the principal quantum number. When considering only this oscillator, the degeneracy of the nth energy level, denoted as \( g_n \), reflects the number of unique state combinations for a given energy and is given by:
\[ g_n = n + 1 \],
where the lowest energy state \( n = 0 \) is non-degenerate, while higher energy levels exhibit higher degrees of degeneracy. This combinatorial aspect of quantum mechanics is crucial for understanding the filling of energy states in systems such as atoms and solid-state crystals which govern much of their electronic properties and behavior.

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Problem 7 A particle of mass \(m\) moves i... [FREE SOLUTION] (3)

Most popular questions from this chapter

A particle of mass \(m\) moves in the three-dimensional potential $$ V(x, y, z)=\left\\{\begin{array}{ll} \frac{1}{2} m \omega^{2} z^{2} & \text { for } 00\\\ +\infty, & \text { elsewhere. } \end{array}\right. $$ (a) Write down the time-independent Schrödinger equation for this particle andreduce it to a set of familiar one-dimensional equations; then find thenormalized wave function \(\psi_{n_{x} n_{v} n_{z}}(x, y, z)\) (b) Find the allowed eigenenergies of this particle and show that they can bewritten as: \(E_{n_{x} n_{y} n_{z}}=E_{n_{x} n_{y}}+E_{n_{z}}\) (c) Find the four lowest energy levels in the \(x y\) plane (i.e.,\(\left.E_{n_{x} n_{y}}\right)\) and their corresponding degeneracies.The wave function of a hydrogen-like atom at time \(t=0\) is $$ \Psi(\vec{r}, 0)=\frac{1}{\sqrt{11}}\left[\sqrt{3}\psi_{2,1,-1}(\vec{r})-\psi_{2,1,0}(\vec{r})+\sqrt{5}\psi_{2,1,1}(\vec{r})+\sqrt{2} \psi_{3,1,1}(\vec{r})\right], $$ where \(\psi_{n l m}(\vec{r})\) is a normalized eigenfunction (i.e., \(\psi_{n lm}(\vec{r})=R_{n l}(r) Y_{I m}(\theta, \varphi)\) ). (a) What is the time-dependent wave function? (b) If a measurement of energy is made, what values could be found and withwhat probabilities? (c) What is the probability for a measurement of \(\hat{L}_{z}\) which yields\(-1 \hbar\) ?Consider a muonic atom which consists of a nucleus that has \(Z\) protons (noneutrons) and a negative muon moving around it; the muon's charge is \(-e\) andits mass is 207 times the mass of the electron, \(m_{\mu^{-}}=207 m_{e} .\) Fora muonic atom with \(Z=6\), calculate (a) the radius of the first Bohr orbit, (b) the energy of the ground, first, and second excited states, and (c) the frequency associated with the transitions \(n_{i}=2 \rightarrown_{f}=1, n_{i}=3 \rightarrow n_{f}=1\), and \(n_{i}=3 \rightarrow n_{f}=2\)Using the fact that the radial momentum operator is given by \(\hat{p}_{r}=-i\hbar \frac{1}{r} \frac{\partial}{\partial r} r\), calculate the commutator\(\left[\hat{r}, \hat{p}_{r}\right]\) between the position operator, \(\hat{r}\),and the radial momentum operator.Consider a hydrogen atom whose wave function is given at time \(t=0\) by $$ \psi(\vec{r}, 0)=\frac{A}{\sqrt{\pi}}\left(\frac{1}{a_{0}}\right)^{3 / 2}e^{-r / a_{0}}+\frac{1}{\sqrt{2 \pi}}\left(\frac{z-\sqrt{2} x}{r}\right)R_{21}(r) $$ where \(A\) is a real constant, \(a_{0}\) is the Bohr radius, and \(R_{21}(r)\) isthe radial wave function: \(R_{21}(r)=1 / \sqrt{6}\left(1 / a_{0}\right)^{3 / 2}\left(r / 2 a_{0}\right)e^{-r / 2 a_{0}}\) (a) Write down \(\psi(\vec{r}, 0)\) in terms of \(\sum_{n l m} \phi_{n lm}(\vec{r})\) where \(\phi_{n l m}(\vec{r})\) is the hydrogen wave function\(\phi_{n l m}(\vec{r})=R_{n l}(r) Y_{l m}(\theta, \varphi) .\) (b) Find \(A\) so that \(\psi(\vec{r}, 0)\) is normalized. (Recall that\(\left.\int \phi_{n^{\prime} l^{\prime} m^{\prime}}^{*}(\vec{r}) \phi_{n lm}(\vec{r}) d^{3} r=\delta_{n^{\prime}, n} \delta_{l^{\prime}, l}\delta_{m^{\prime}, m} .\right)\) (c) Write down the wave function \(\psi(\vec{r}, t)\) at any later time \(t\). (d) Is \(\psi(\vec{r}, 0)\) an eigenfunction of \(\hat{L}^{2}\) and \(\vec{L}_{2}\)? If yes, what are the eigenvalues? (e) If a measurement of the energy is made, what value could be found and withwhat probability? (f) What is the probability that a measurement of \(\hat{L}_{z}\) yields \(1\hbar\) ? (g) Find the mean value of \(r\) in the state \(\psi(\vec{r}, 0)\).
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Problem 7 A particle of mass \(m\) moves i... [FREE SOLUTION] (2024)

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